1. Sep 9, 2011

### thaolieu

A golfer lines up for her first putt at a hole that is 13.5 exactly northwest of her ball’s location. She hits the ball 13.5 and straight, but at the wrong angle, 40 degree from due north.

a)In order for the golfer to have a “two putt green,” determine the angle of the second putt.
Angle= ? degree in south of west

b)Determine the magnitude of the second putt's displacement.

2. Sep 9, 2011

### lewando

Welcome, thaolieu, to PF. The idea here is that if you show some effort at working out the problem then help can be provided. So I must ask you, what have you tried? Can you draw a picture of the situation? What are you confused about, etc.

3. Sep 9, 2011

### thaolieu

I drew the graph that indicate the direction of the ball and putt #1.
Direction of the ball = -13.5x +0y
Putt 1 = 13.5 cos (40)x + 13.5sin (40)y = -3.16x + 8.67y

That's what I got. I hope to receive help to go further. Thank you so much

4. Sep 10, 2011

### lewando

This is a little ambiguous, let's agree that the golfer is a pretty good putter so this direction is really 40 degrees WEST of NORTH.

To start, your graph should contain 2 vectors: the location of the hole and the location of the ball after the first putt. Can you post your graph, with all the information, to make sure you are starting out correctly?

This is a location vector pointing WEST. Please recheck what you are trying to do here. Convention: +x = EAST, +y = NORTH

When you graph -3.16x + 8.67y, does it look right? Specifically, does the angle look like 40 degrees, or not? Does the magnitude = 13.5, or not?

Last edited: Sep 10, 2011