# Vector Coordinate Conversions

1. Feb 9, 2008

### EugP

1. The problem statement, all variables and given/known data
Transform the following vector into cylindrical coordinates and then evaluate them at the indicated points:

$$\vec A = (x + y)\hat x$$

at

$$P_1 (1, 2, 3)$$

2. Relevant equations
$$r = \sqrt{x^2 + y^2}$$

$$\phi = \tan^{-1}(\frac{y}{x})$$

$$z = z$$

3. The attempt at a solution
$$r = \sqrt{x^2 + 0^2} = x$$

$$\phi = \tan^{-1}(\frac{0}{x}) = 0$$

$$z = z = 0$$

$$\vec A = x\hat r$$ at point $$P_1 (1, 2, 3) \Longrightarrow \hat r$$

Could someone please check if this is correct? There are a few more of these, but if I can do this one, then the rest are no problem. Thanks.

Last edited: Feb 9, 2008
2. Feb 9, 2008

### HallsofIvy

Staff Emeritus
Can I assume that $\hat{x}$ is the unit vector in the x direction? If so then $(x+ y)\hat{x}$ is not a "vector", it is a "vector field"- a vector at each point in the xy-plane. At (1, 2, 3) (surprising how often that point shows up!), that is the vector $3 \hat{x}$, of length 3 pointing in the x-direction. That vector has no z-component. The projection of the vector <2, 0> in the direction of the <1, 2> vector will be the $\hat{r}$ component. <2, 0> minus that projection will be the component in the $\theta$ direction.

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