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Two vectors A and B have magnitude A = 3 and B = 3. Their vector product is A X B = -5k+2i. What is the angle Between A and B.

OK so I'll start with what I do know.

I do know that the cross product is the magnitude of A times magnitude of B times sin theta of B.

I end up with

3*3sinTHETA = 5.4 ( i got 5.4 from finding the magnitude with the components that they gave me )

eventually getting an angle of 37 degrees by dividing by 9 and using arcsin

im not sure what this angle is though..I think it is the angle of B but if it is how does that help me to find the angle between A and B ?