- #1

- 565

- 2

What is the cross product of -i x i? Is it negative 1 or is still just 0?

- Thread starter Ry122
- Start date

- #1

- 565

- 2

What is the cross product of -i x i? Is it negative 1 or is still just 0?

- #2

Defennder

Homework Helper

- 2,591

- 5

Now what is the vector product of a vector with itself?

- #3

- 565

- 2

where

u=-i+2j and v=i+2j is

v=(3/5)i+(6/5)j ?

The answer i got was (4/5)i + (8/5)j

i used the equation

w=v.((u.v)/(modulusv^2))

- #4

- 15,393

- 685

This equation for the projection isi used the equation

w=v.((u.v)/(modulusv^2))

[tex]\mathbf w = \mathbf v \frac {\mathbf u \cdot \mathbf v}{v^2}[/tex]

Note well: The cross product is not involved when you compute the projection this way.

- #5

- 565

- 2

- Last Post

- Replies
- 10

- Views
- 22K

- Last Post

- Replies
- 5

- Views
- 2K

- Last Post

- Replies
- 5

- Views
- 12K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 11

- Views
- 24K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 8

- Views
- 3K

- Last Post

- Replies
- 3

- Views
- 5K

- Last Post

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 4K