- #1

- 565

- 2

What is the cross product of -i x i? Is it negative 1 or is still just 0?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Ry122
- Start date

- #1

- 565

- 2

What is the cross product of -i x i? Is it negative 1 or is still just 0?

- #2

Defennder

Homework Helper

- 2,591

- 5

Now what is the vector product of a vector with itself?

- #3

- 565

- 2

where

u=-i+2j and v=i+2j is

v=(3/5)i+(6/5)j ?

The answer i got was (4/5)i + (8/5)j

i used the equation

w=v.((u.v)/(modulusv^2))

- #4

- 15,415

- 687

This equation for the projection isi used the equation

w=v.((u.v)/(modulusv^2))

[tex]\mathbf w = \mathbf v \frac {\mathbf u \cdot \mathbf v}{v^2}[/tex]

Note well: The cross product is not involved when you compute the projection this way.

- #5

- 565

- 2

Share: