(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A primate research station attaches a tiny radio transmitter to a chimpanzee born in captivity before releasing it into the wild. One day, the station picks up a signal indicating the chimp is 5000 m from the station in a direction 21° S of W. Over the next day, the chimp wanders 3000 m in a direction 38° N of E. At this point,

(a) how far from the station and

(b) in what direction (as a positive angle measured counterclockwise from east) is the chimp? (Hint: Take east as the +x direction, and north as the +y direction.)

2. Relevant equations

A_{x}= A cos θ

A_{y}= A sin θ

For Magnitude

[tex]\stackrel{\rightarrow}{r}[/tex] = [tex]\sqrt{A^{2}_{x} + A^{2}_{y}}[/tex]

For Direction

θ tan^{-1}[tex]\frac{A_{y}}{A_{x}}[/tex]

3. The attempt at a solution

(a) 2303 m

(b) What does it mean?

I use the direction equation but thats not correct. I had to do with counterclockwise direction that I do not know how to do.

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# Homework Help: Vector, Direction question

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