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Homework Help: Vector equation help

  1. Sep 25, 2010 #1
    1. The problem statement, all variables and given/known data

    An airplane flies at an airspeed of 459 km/hr. The pilot wants to fly 784 km to the north. She knows that she must head 21.6° east of north to fly directly there. If the plane arrives in 2.07 hr, find the magnitude of the wind velocity vector.

    Tried solving as seen below but I'm not sure where I'm going wrong.
    2. Relevant equations



    3. The attempt at a solution
    v=d/t
    459 km/h=d/2.07 h
    950.13 km=d

    srt(950.13^2-784^2)=b
    66.05 km=b

    v=66.05 km/2.07 h
    v=31.9 km/h
     
    Last edited: Sep 25, 2010
  2. jcsd
  3. Sep 25, 2010 #2

    Astronuc

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    Staff Emeritus
    Science Advisor

    Re: Need Help - Airspeed Vectors

    The plane flies in the air at a speed of 459 km/h for 2.07 hrs, so the distance is correct. However, the plane flies at an angle of 21.6 deg E of N. What is the projection from the planes trajectory in the air on to due north?
     
  4. Sep 25, 2010 #3
    Re: Vectors

    it would be: 459cos21.6=426.77 km/h
     
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