# Vector Equations of Lines

1. Aug 29, 2008

### roam

Find the parametric equations of the lines L1, L2, L3 and L4 that pass through the indicated verticies of the square:

http://img516.imageshack.us/img516/4052/parametrickl6.jpg [Broken]

This isn't a homework question but I need some tutoring help here with parametric equations of lines, those who are good at linear algebra. Thanks.

3. The attempt at a solution

L1 for example, is parallel to the y-axis a vector that's (0,1)

A vector equation of the line is x=tv. If we let x = (x,y) this equation can be expressed in the component form as;

(x,y) = t(0,1)

(t is some scalar.)

Therefore the parametric equation has to be:

x = t.0
y = t

$$\Rightarrow x = 0, y = t$$

But the correct answer in the textbook suggests: L1: x = 1, y = t

Why did I get the wrong answer for x?

I'm pretty confused right now I've been reading the book this afternoon and I still don't get it, I’m too tired to continue, I’m off to bed now!

Last edited by a moderator: May 3, 2017
2. Aug 30, 2008

### danago

You are right that L1 is parallel to the vector (0,1), but when t=0, your equation suggest that (x,y)=(0,0) which cannot be correct, since the line does not pass through the origin. Can you see the detail you have overlooked?

3. Aug 30, 2008

### Defennder

No it isn't. A vector equation is of the form $$\vec{OR} + t\vec{v}$$. Assuming that you meant that the x-component of the line is x=tv where v is a vector, it's still incorrect because x is constant for L1, and doesn't vary for any parameter t.