# Vector field

likephysics

## Homework Statement

$$\int$$ delxA dv = -$$\oint$$ Axds

where A is a vector field
Left hand side is integral over volume. Right hand side is integral over closed surface.

## The Attempt at a Solution

Can't understand what Axds means.

payumooli
A is the vector field
and dS is the closed surface on which you want to see the flux
x is a multiplication symbol

$$\vec R = \vec R(u,v) = \langle x(u,v),y(u,v),z(u,v)\rangle$$
$$d\vec S = \vec R_u \times \vec R_v\, dudv$$