# Homework Help: Vector field

1. Feb 2, 2010

### likephysics

1. The problem statement, all variables and given/known data

$$\int$$ delxA dv = -$$\oint$$ Axds

where A is a vector field
Left hand side is integral over volume. Right hand side is integral over closed surface.

2. Relevant equations

3. The attempt at a solution

Can't understand what Axds means.

2. Feb 2, 2010

### payumooli

A is the vector field
and dS is the closed surface on which you want to see the flux
x is a multiplication symbol

3. Feb 2, 2010

### LCKurtz

Presumably what you are calling ds (which is usually used for an element of arc length) should be the vector surface element. If the surface is parameterized as

$$\vec R = \vec R(u,v) = \langle x(u,v),y(u,v),z(u,v)\rangle$$

the surface element is

$$d\vec S = \vec R_u \times \vec R_v\, dudv$$