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Let

[tex]\vec{F}=(1/(x+2), 1, y)[/tex].

The field line that passes through(2, 3, 1)also passes through the point(3, y, z).

What is tan(y+2z)?

Let [tex]\vec{r}_1=(2, 3, 1), \vec{r}_2=(3, y, z)[/tex]

Since the field line passes through both points, we have

[tex]\vec{F}(2, 3, 1)//(\vec{r}_2-\vec{r}_1)[/tex]

hence when cross multiplied, it should equal zero!

However, I am not getting the right answer using this approach. Can someone pinpoint where I perhaps have made an error?

Thanks!

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# Homework Help: Vector Field

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