Three forces, given by 1 = ( -2.35 i - 2.10 j ) N, 2 = ( 4.90 i + 3.05 j ) N, and 3 = (49.0 j ) N, act on an object to give it an acceleration of magnitude 3.65 m/s2.
(a) What is the direction of the acceleration?
86.1° (from the positive x axis)
(b) What is the mass of the object?
(c) If the object is initially at rest, what is its speed after 10.0 s?
(d) What are the velocity components of the object after 10.0 s?
(____ i + ____ j) m/s
F = ma
Vf = Vi + at
The Attempt at a Solution
F = ma
m = F/a
To find mass (kg), I divided 2.55 by 3.65 and got 0.7 kg as the answer. That should be the correct answer but it isn't. Can someone please tell me what I did wrong? Thanks.