# Vector kinematics question

1. Sep 11, 2010

### ihatecats2014

1. The problem statement, all variables and given/known data
Exactly 3.3s after a projectile is fired into the air from the ground, it is observed to have a velocity v = (8.6i + 5.0j ), where the x axis is horizontal and the y axis is positive upward.

Determine the horizontal range of the projectile

2. Relevant equations
x=x0+vy0t+1/2at2
v=$$\sqrt{}Vx$$2+Vy2

3. The attempt at a solution
v= 9.95 by finding the resultant of the velocity vector
x 0 = 0
ax= 0
x= Vx(t)?
is that correct?
if so then,
x= 9.95(3.3)= 32.8?
but this is wrong and i don't know how to get it
wait does R= x? or y?

Last edited: Sep 11, 2010
2. Sep 12, 2010

### kuruman

Use the information that v = (8.6i+5.0j)m/s in 3.3 s to find the components of the initial velocity vector. Then use the equation that relates the range R to these initial components to answer the question.