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Hey guys I need your help on this one. There is something I am doing wrong on this problem. Can you help me figure out what I am doing wrong?

Problem: A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.66m north, the second 1.83m southeast, and the third 0.91m southwest. What are (a) the magnitude and (b) the direction of the displacement needed to get the ball into the hole on the first putt?

vector a = 3.66

vector b = 1.83

vector c = 0.91

So far I have drawn a graph with vector a 3.66m directly due north. Then from the head of that vector drawn vector b 1.83m directly southeast, and from that

I have drawn vector c 0.91m directly southwest.

unit vector notation:

A = (0)i + (3.66)j

B = (1.83cos(45))i + (1.83sin(45))j

C = (.91cos(45))i + (.91sin(45))j

R = A + B + C

R = 1.37i + 5.74j

R = [1.37^2 + 5.74^2]^1/2 = 5.90

Answers (a) 1.8m (b) 69 degress north of due east.

What am I doing wrong to derive the answer?

Any help is appreciated. Thanks

Problem: A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.66m north, the second 1.83m southeast, and the third 0.91m southwest. What are (a) the magnitude and (b) the direction of the displacement needed to get the ball into the hole on the first putt?

vector a = 3.66

vector b = 1.83

vector c = 0.91

So far I have drawn a graph with vector a 3.66m directly due north. Then from the head of that vector drawn vector b 1.83m directly southeast, and from that

I have drawn vector c 0.91m directly southwest.

unit vector notation:

A = (0)i + (3.66)j

B = (1.83cos(45))i + (1.83sin(45))j

C = (.91cos(45))i + (.91sin(45))j

R = A + B + C

R = 1.37i + 5.74j

R = [1.37^2 + 5.74^2]^1/2 = 5.90

Answers (a) 1.8m (b) 69 degress north of due east.

What am I doing wrong to derive the answer?

Any help is appreciated. Thanks

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