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Vector pathes and directions

  1. Dec 5, 2003 #1
    a person walks 80.0 paces E
    50.0 paces 70.0 degrees N of E
    18 paces N
    40 paces W

    I made a chart

    NS EW these are directions
    0 +80
    +47 +17.1 got this by using 50*sin70 and 50* cos 70
    +18 0
    0 -40
    sum is
    65 57.1

    I redrew my vector digram

    to find D (distance)
    d^2 = 65^2 +57.1^2
    d = 86.5 paces
    tan-1 (65/57.1)
    48.7 degrees

    So the answer i got was 86.5 paces @ 48.7 degrees N of E

    is that right?
  2. jcsd
  3. Dec 5, 2003 #2
    Now if I sent you this message:
    would you have the slightest idea what in the world I'm talking about?

    Why don't you post your question in some clear and orderly fashion, such as:
    The x-coordinate is bla, bla, bla...

    The y-coordinate is bla, bla, bla...

    and so on, so people don't have to first figure out your secret code before they can even begin to think about the answer.

    (Organizing your thoughts this way might even help you answer it yourself.)

    Sorry if you think that's an unreasonably grumpy response.[b(]
  4. Dec 5, 2003 #3

    Doc Al

    User Avatar

    Staff: Mentor

    I agree with gnome, but I was able to break your secret code. (For some reason, you list y first, then x.)

    You did it perfectly. :smile:
  5. Dec 5, 2003 #4
    sorry for the mass confusion but the prof like to us the north , south east and west for the directions and of course north and south and on the y axis and E&W are on the X axis the reason i put the Y axis first is so when i am finding theata y/x seems simple in mind but i can see where i really messed up
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