A particle is located at the vector position =(9.00 + 10.00) m and a force exerted on it is given by =(7.00 + 6.00) N. Consider another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude. Multiple such points can exist. Only one such point can lie on the y-axis Determine the position vector of such a point _____ j m 2. Relevant equations: dot products 3. The attempt at a solution: I've taken the torque (-16) and divided by 2, kept F as (7,6) and kept x of the position vector...I got 6.57 for the y but it was wrong.