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Vector products and torque

  1. Apr 21, 2004 #1
    A particle is located at the vector position r = (i + 3 j) m, and the force acting on it is F = (5 i + 6 j) N.
    (a) What is the torque about the origin?
    (b) What is the torque about the point having coordinates (0, 4) m?

    when you are given an i + j, do you assume that it starts at the origin?
    then to you add 4 to the j vector since you are changing the point to (0,4)?
     
  2. jcsd
  3. Apr 21, 2004 #2

    chroot

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    Torque is defined as the cross product r x F, right?

    You're given two vectors: r = (i + 3j) m, and F = (5i + 6j) N.

    It sounds to me like you're missing the crucial ingredient that the representation r = (i + 3j) is the same as the "vector notation" (1, 3, 0); the representation (5i + 6j) is the same as (5, 6, 0). Can you calculate the vector cross product of those two vectors?

    - Warren
     
  4. Apr 21, 2004 #3
    Use matrix
     
  5. Apr 24, 2004 #4

    Doc Al

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    Yes, assume that the "position vector" is with respect to the origin (0,0,0).
    Since torque is always calculated with respect to (wrt) some point*, when you change that point from (0,0) to (0,4) you must use a new position vector with respect to that new reference point:
    Let A = position of particle wrt 0,0 = 1,3
    Let B = position of new reference point wrt 0,0 = 0,4
    Let C = position of particle wrt 0,4 = ???
    You know that A = B + C, so figure out the new position vector C.

    *assumed to be in the z = 0 plane in this problem
     
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