# Vector Question

Gold Member

## Homework Statement

A Family has a boat which can travel at 12 m/s in still water. They are using it to reach a point 500m downstream on the other side of a river 300m wide, and flowing at 4 m/s. What heading must they take, relative to their starting point, in order to reach their destination?

## The Attempt at a Solution

I first drew a triangle, with the side parallel to the river banks 500m, and the side perperndicular 300m. From there, i found that to end up 500m downstream, the resultant direction of travel should be ~59 degrees from the perpendicular (or 31 degrees from the bank).

The rivers current plus the boats motion should result in a velocity in the direction of 59 degrees. So:

$$\left( {\begin{array}{*{20}c} 4 \\ 0 \\ \end{array}} \right) + \left( {\begin{array}{*{20}c} {12\sin \theta } \\ {12\cos \theta } \\ \end{array}} \right) = \lambda \left( {\begin{array}{*{20}c} {100\sqrt {34} \sin 59} \\ {100\sqrt {34} \cos 59} \\ \end{array}} \right)$$

I solved for theta, and found that it equals 49 degrees. So i concluded that to end up 500m downstream, the boat should set off at 49 degrees to the perpendicular of the banks.

Im unsure if that is correct. Also, is there a better way i should have gone about it?

Thanks,
Dan.