- #1
mathmathmad
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Homework Statement
Find the dimnesion and a basis of vector space V
Homework Equations
V is the set of all vectors (a,b,c) in R^3 with a+2b-4c=0
The Attempt at a Solution
(4c-2b,b,c) = b(-2,1,0) + c(4,0,1)
so {(-2,1,0),(4,0,1)} is the basis of the SUBSPACE of V right?
how do I get the 3rd linearly independent vector so that it forms the basis of V?
Is it (1,0,0)? (0,1,0) seems possible... but the basis of a vector space isn't unique right?