Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Vector spaces

  1. Oct 16, 2004 #1
    I have :
    c1(t+1) + c2(t^2 + 2) + c3(t^2 -t) = 0 for all t.
    by specifying different values of t. I get
    t=-1: 3c2 + 2c3=0
    t=0: c1+2c2 =0
    t=1:2c1 + 3c2 =0

    How can I check that the only solution is c1=c2=cc3=0 ?
     
  2. jcsd
  3. Oct 16, 2004 #2

    arildno

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    Simply solve the system of equations you've just made for c1,c2,c3.
     
  4. Oct 16, 2004 #3
    that's the problem I don't know how. I know it's simple but I just can't figure it out?
     
  5. Oct 16, 2004 #4

    arildno

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    You have 3 equations in 3 unknowns; you've seen that before?
     
  6. Oct 16, 2004 #5
    I've done this when I have a matrix in reduce or reduce echelon but then I only have x1 in one linem here I have c1 in 2nd and 3rd row and it's there I am stuck. I admit I'm not very good at this. If you possibly can would you be so kind to lead my on with this problem?? :smile:
     
  7. Oct 16, 2004 #6

    arildno

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    Why don't you just interchange line 1 and line 3?
    Interchanging "topmost equation" with "bottom-most equation" can't possibly change the solution, or what?
     
  8. Oct 16, 2004 #7
    I got it. Thanks a lot :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Vector spaces
  1. Vector spaces (Replies: 10)

  2. Vector space (Replies: 16)

  3. Vector space (Replies: 2)

  4. Vector spaces (Replies: 6)

  5. Vector space (Replies: 4)

Loading...