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Absolut10
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Homework Statement
An object is traveling N59.5E at 5.5 m/s
It experiences an acceleration of 4.4 m/s^2, S76.6E for 1.5 Seconds
When it ends it proceeds for 2.6 seconds with no acceleration
Then is experiences a second acceleration of 4.4 m/s^2, N59.5E for 2.1 seconds
I need to find out the velocity at the end of the two accelerations and draw a diagrm of the path taken by the object
Homework Equations
d=v1t + 1/2at^2
Sine Law
The Attempt at a Solution
I proceeded to find the resultant velocity's magnitude by doing the sqaure root of 5.5^2 + 6.6^2, then using sine law to find the direction of 41.45 degrees. I know i now have to do it again 2 times but i was wondering if this was right?