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Vectors and projectiles

  1. Nov 29, 2011 #1
    1. The problem statement, all variables and given/known data
    A plane heads out to L.A with a velocity of 220m/s in a NE direction, relative to the ground, and encounters a wind blowing head-on at 45m/s, what is the resultant velocity of the plane, relative to the ground.


    2. Relevant equations

    Pythagorean Theorem ?
    Simple subtraction

    3. The attempt at a solution
    Here is an Image I made in paint to help visualize the solution of the problem... I believe I'm not solving this correctly.


    http://img443.imageshack.us/img443/9841/physics1.jpg [Broken]

    Uploaded with ImageShack.us

    I'm pretty much grabbing in the dark here since I cannot understand everything. Sorry for wasting your time in a way.
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Nov 29, 2011 #2

    cepheid

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    NE is at a bearing of 45 degrees so that that "northerly" component of the plane's velocity is (220 m/s)cos(45 deg) and the "easterly" component is (220 m/s)sin(45 deg). Now, the westward wind doesn't affect the velocity along the N-S axis, but it does affect the velocity along the E-W axis. Taking east to be the positive direction and west to be the negative direction along the E-W axis, the new velocity along this axis is:

    (220 m/s)sin(45 deg) - 45 m/s = v_ew

    (where I've given it a name, to remove clutter).

    The resultant total velocity is easy to find. The N-S and E-W components still form a right triangle, so that the sum of their squares is equal to the square of the total velocity (in magnitude):

    (v_total)^2 = [(220 m/s)cos(45)]^2 + (v_ew)^2

    EDIT: you can also get the angle of the resultant from this same triangle.
     
  4. Nov 29, 2011 #3
    Doesn't the problem say a head on wind? where are you getting westerly?
     
  5. Nov 29, 2011 #4

    cepheid

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    Good call, I got it from the OP's diagram, but I see now that the OP was just wrong.

    To the OP: if the two vectors lie along the same line, you can add them by simply adding their magnitudes (or subtracting them if they are in opposite directions).
     
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