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Vectors city to city problem

  1. Sep 3, 2010 #1
    1. The problem statement, all variables and given/known data

    An airplane flies 200 km due west from city A to city B and then 345 km in the direction of 34.5° north of west from city B to city C. In straight-line distance, how far is city C from city A? Relative to city A, in what direction is city C?

    2. Relevant equations

    The Pythagorean theorem

    3. The attempt at a solution

    398.78 km
  2. jcsd
  3. Sep 3, 2010 #2
    Re: Vectors

    The Pythagorean theorem is about right-angled triangles. The triangle ABC in your problem is not right-angled.

    The way to solve this would be: draw the situation, then try to make some right-angled triangle, calculate the length of its sides using sine and cosine functions and then use the Pythagorean theorem.
  4. Sep 3, 2010 #3
    Re: Vectors

    I dont know how to draw 34.5 degrees north of west.
  5. Sep 3, 2010 #4
    Re: Vectors

    Yeah I can understand that, I do not find it very clear terminology either, but I am assuming they meant rotating the negative x-axis (i.e. west) 34.5 degrees in clockwise direction (i.e. towards north).
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