Vectors cross product

  • #1
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Homework Statement



Find the set of points of M such that:
AM x BC=AM x AC (Vectors)



The Attempt at a Solution

[/b]
AM x (BM+MC) =AMx(AM+MC)
AMxBM+AMxMC=AMxAM +AM x MC
Then AMxBM=0
MA X MB=0

I am new to this lesson and this is my first time i solve such a question and i had no idea how to solve it but i tried my best please some help give me some hints, Thank you.
 
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  • #2
SammyS
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  • Homework Statement

Find the set of points of M such that:
AM x BC=AM x AC (Vectors)



The Attempt at a Solution


AM x (BM+MC) =AMx(AM+MC)
AMxBM+AMxMC=AMxAM +AM x MC
Then AMxBM=0
MA X MB=0[/B]

I am new to this lesson and this is my first time i solve such a question and i had no idea how to solve it but i tried my best please some help give me some hints, Thank you.
If AM × BM = 0 , then how is AM oriented relative to BM ?
 
  • #3
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If AM × BM = 0 , then how is AM oriented relative to BM ?
Right-handed
 
  • #4
SammyS
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Right-handed
Do you mean that they form a right angle?

Yes, they do.

Look at two fixed points, A and B, in a plane. Consider where point M can lie, if vector, AMBM . Now consider all such locations point M can occupy.
 
  • #5
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Do you mean that they form a right angle?

Yes, they do.

Look at two fixed points, A and B, in a plane. Consider where point M can lie, if vector, AMBM . Now consider all such locations point M can occupy.
Thanks for the help.
 
  • #6
SammyS
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Thanks for the help.
To be sure that you fully understand:

What is your final conclusion regarding the set of points on which point M can lie?
 

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