1. The problem statement, all variables and given/known data A mass of 100 kg is suspended by two ropes that make an angle of 60 degrees to the horizontal. If a horizontal pull of 200N, in a plane perpendicular to the plane of the other forces is applied find the tensions in the ropes after equilibrium has occurred. 2. Relevant equations Component Method 3. The attempt at a solution T1cos60=T2cos60 T2=(T1cos60)/(cos60) Fx=-T1cos60+T2cos60 Fy=T1sin60+T2sin60-Fg Sub in T2 into equation Fy=T1sin60+T2sin60-Fg = (T1sin60)+((T1cos60)/(cos60))(sin60) = T1sin60+T1(0.866) =T1(sin60+0.866)=(100)/(9.8) T1=T2=565.8 Can someone please tell me if I did this right?