- #1

viet1919

- 8

- 0

## Homework Statement

What is the magnitude and angle to

Vector B - 2(Vector A)?

## Homework Equations

A sub x: 44cos28 = 38.85

A sub y: 44sin28 = 20.66

B sub x: 26.5cos56 = 14.82 <-- (Does the negative sign matter in 26.5? My teacher said it's not)

B sub y: 26.5sin56 = 21.97

## The Attempt at a Solution

I multiplied the Vector A's by two.

A sub x: 38.85 x 2 = 77.7

A sub y: 20.66 x 2 = 41.2

I then solved for the x and y components.

x: (77.7) + (14.82) = 92.52

y: (41.2) - (21.97) = 19.23

Then I solved for the magnitude and angle.

Magnitude:

[itex]\sqrt{}[/itex](92.52)

^{2}+ (19.23)

^{2}= 94.50

Angle: tan

^{-1}= 19.23/92.52 --> 11.74°

Is this correct? I have a weird feeling that it's wrong. I feel like I am missing something some wear. I really can't tell.