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Introductory Physics Homework Help
How do I solve this vector problem involving three ropes and a rough surface?
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[QUOTE="y90x, post: 5889514, member: 635402"] [h2]Homework Statement [/h2] I’m working on a problem that requires adding 3 vectors . And while I was following the book, it said to find the angle to divide the y over the x components of the resistant , and showed the angle to be -1.25 but then follow d to change to -51 . How did it change ? The book doesn’t explain I’ll inclide a photo of the textbook so you can see what I’m talking about Here’s the problem I’m working on just in case: Three horizontal ropes are tied to a 30 kg mass resting on a rough surface. The coefficient of friction between the mass and the surface is 0.12. Rope A has tension 60 N directed Northwest, rope B has tension 70 N directed 20° East of South, and rope C has tension 80 N directed 35 North of West. Find the resulting acceleration of the 30 kg mass. [h2]Homework Equations[/h2] The component method for adding vectors [h2]The Attempt at a Solution[/h2] Rope A : -60cos(45) + 60sin(45)= A -42.426 + 42.426 = A Rope B : 70cos(20) + -70sin(20) = B 65.778 + -23.94 Rope C: -80cos(35) + 80sin(35) = C -65.532 + 45.886 = C To find the resultant magnitude : Square root of ( all the X components added up) (-42,1800)^2 + 64.3711^2 ( all the Y components added up) = 76.959 To find the angle : Pheta = tan^(-1)(Y/X) = tan^(-1) (64.3711/-42.1800) = -56.8 Solution of the actual problem : 1.72 m/s^2 at 15.0 north of westhttps://www.physicsforums.com/attachments/215616 [/QUOTE]
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How do I solve this vector problem involving three ropes and a rough surface?
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