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Vectors & Projectile Motion

  1. Sep 10, 2009 #1
    1. The problem statement, all variables and given/known data
    A basketball leaves a player's hands at a height of 2.15m above the floor. The basket is 3.05m above the floor. The player likes to shoot the ball at a 40-degree angle.

    If the shot is made from a horizontal distance of 10.00m and must be accurate to +0.32m (horizontally), what is the range of initial speeds allowed to make the basket?


    2. Relevant equations
    sinx = opposite side/hypotenuse


    3. The attempt at a solution
    What I attempted to do was draw two right-angled triangles /| with a 40-degree angle, a 0.9m vertical side and a variable horizontal side (9.68m/10.32m) and tried to figure out the hypotenuse, but it doesn't seem right...
     
  2. jcsd
  3. Sep 10, 2009 #2

    rl.bhat

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    What is the relevant equation of the projectile motion?
     
  4. Sep 11, 2009 #3
    final velocity = initial velocity + (9.80)(time)? I don't really get which p.m. equation would apply...
     
  5. Sep 11, 2009 #4

    rl.bhat

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    The equation can be written as
    y = yo + x*tanθ - 1/2*g*x2/(v*cosθ)^2
    Solve for v.
     
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