Question: A rolling ball has an initial velocity of -1.5 m/s. a. If the ball has a constant acceleration of -0.23 m/s^2, what is its velocity after 2.2s? b. What was its average velocity during that time interval? c. How far did it travel in this time interval? So far i got: a. V= initial velocity + acceleration(time) (-1.5m/s) + (-0.23m/s^2)(2.2s)=-2.006m/s b. i know the formula for average velocity V= (d2- d1) / (t2 -t1). My problem is I'm not sure what to plug in for displacement. for time i plugged in 2.2s -0s this is where i am stuck. c. Im not sure of the formula to solve this part.