- #1
Jess048
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Question: A rolling ball has an initial velocity of -1.5 m/s.
a. If the ball has a constant acceleration of -0.23 m/s^2, what is its velocity after 2.2s?
b. What was its average velocity during that time interval?
c. How far did it travel in this time interval?
So far i got:
a. V= initial velocity + acceleration(time)
(-1.5m/s) + (-0.23m/s^2)(2.2s)=-2.006m/s
b. i know the formula for average velocity V= (d2- d1) / (t2 -t1). My problem is I'm not sure what to plug in for displacement. for time i plugged in 2.2s -0s this is where i am stuck.
c. I am not sure of the formula to solve this part.
a. If the ball has a constant acceleration of -0.23 m/s^2, what is its velocity after 2.2s?
b. What was its average velocity during that time interval?
c. How far did it travel in this time interval?
So far i got:
a. V= initial velocity + acceleration(time)
(-1.5m/s) + (-0.23m/s^2)(2.2s)=-2.006m/s
b. i know the formula for average velocity V= (d2- d1) / (t2 -t1). My problem is I'm not sure what to plug in for displacement. for time i plugged in 2.2s -0s this is where i am stuck.
c. I am not sure of the formula to solve this part.