A 300 g bird flying along at 6.0 m/s sees a 10 g insect heading straight toward it with a speed of 30m/s. The bird opens its mouth wide and enjoys a nice lunch. What is the bird’s speed immediately after swallowing? Relevant equations Jx = m(Vx)f - m(Vx)i Jy = m(Vy)f - m(Vy)i Given m(b) = 0.3 kg v(b) = 6.0 m/s m(i) = 0.01 kg v(i) = 30 m/s The attempt at a solution Jx = (0.01)(30) - (0.3)(6.0) = 0.12kg.m/s 0.12kg.m/s * 1/0.3kg = 0.4 m/s ????