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Velocity and Displacement

  1. Sep 28, 2009 #1
    1. The problem statement, all variables and given/known data

    A particle's initial velocity is given by v0x = -1.0m/s and v0y = 3.0m/s; it's acceleration is ax = 0.50m/s2 and ay = -0.90m/s2. (a) Calculate its velocity 2.0s later. (b) Calculate its displacement at that time.

    2. Relevant equations

    vx = v0x + axt
    ∆x = v0xt + 1/2axt2
    ∆y = v0yt + 1/2ayt2

    3. The attempt at a solution

    v = -1.0m/s(x hat) + 3.0m/s(y hat)
    a = 0.5m/s2(x hat) - 0.9m/s2(y hat)

    Solve for velocity at 2.0s
    vx = v0x + axt
    vx = (-1m/s) + (0.5m/s2)(2.0s)
    vx = 0m/s

    vy = v0y + ayt
    vx = (3m/s) + (-0.9m/s2)(2.0s)
    vx = 1.2m/s

    v = 0m/s(x hat) + 1.2m/s(y hat)

    Calculate displacement.
    ∆x = v0xt + 1/2axt2
    ∆x = (-1m/s)(2.0s) + 1/2(0.5m/s2)(2.0s)2
    ∆x = -1m

    ∆y = v0xt + 1/2axt2
    ∆y = (3m/s)(2.0s) + 1/2(-0.9m/s2)(2.0s)2
    ∆y = 4.2m

    y = -1.0m(x hat) + 4.2m(y hat)
     
  2. jcsd
  3. Sep 29, 2009 #2

    Redbelly98

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    Looks good.
     
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