(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Boxes are placed on a chute at a uniform rate of time T_{r}and slide down the chute with uniform acceleration. Knowing that as any box B is released, the preceeding box A is 6m down the chute; 1 second later there is a 10m distance between them. Determine the value of T_{r}

2. Relevant equations

3. The attempt at a solution

As x = 0.5at^{2}

6 = 0.5a(T_{r})^{2}

I found a to be (change in y) / (change in x) = 4 m/sec^{2}

So, [tex]\sqrt{6/(0.5*0.4)}[/tex] = 3^(0.5) = T_{r}

But the answer is plain old 3...

Any advice appreciated :)

Adrian

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# Homework Help: Velocity and Time

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