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Velocity as a function of time?

if an object has an acceleration of 22.3 m/s^2 [63.9 degrees E of S]

what is its "velocity as a function of time"

not sure what that means.. any ideas?
 

quasar987

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bullroar_86 said:
if an object has an acceleration of 22.3 m/s^2 [63.9 degrees E of S]

what is its "velocity as a function of time"

not sure what that means.. any ideas?
It means you have to find a function v(t) that relates the speed of the object, and the time elapsed.

Hint: The answer is in the definition of (constant) acceleration.
 
13
0
v=vnot+at
vnot equals acceleration from the beginning of the problem.
v= velocity at a given time.
 

HallsofIvy

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ayalam said:
v=vnot+at
vnot equals acceleration from the beginning of the problem.
v= velocity at a given time.
No, in that equation, "vnot" has to be the velocity at t= 0. And be sure to note that the velocity is a vector, not just a number.
 

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