Starting from rest an 11kg block slides 11.9m down a frictionless ramp (inclined at 30° from the floor) to the bottom. The block then slides an additional 26.3m along the floor before coming to a stop. The acceleration of gravity is 9.8 m/s^2. Find the speed of the block at the bottom of the ramp.
Conservation of energy: Ebefore=Eafter
The Attempt at a Solution
I tried solving this two differant ways, and both gave me the same answer, which was wrong. First I tried kinematics.
(I used 9.8/sin30 because 9.8 is the vertical component, so 9.8/sin30 is the acceleration down the ramp)
The other way I tried used conservation of energy.
I don't see where I went wrong in my logic, so I would greatly appreciate some guidance. Thank you!