Velocity down a slope

11
0
Hi

Question is-

In the assesment of a buffers performance railway wagon of mass 6 tonne is allowed to roll freely down an incline of 1 in 20 Sine for a distance of 50M into a horizontal yard. At the end of yard is brought to rest by a pair of parrallel springs. The stiffness in each spring is 30kN/m and the intial resistance is 4.5kN. Calculate comprssion of springs.

I can to the final part once I know speed of inpact on springs.

I cant work out speed on wagon as point of impact.
The length of slope is 50m and height will be (50/20 which is 2.5m). I just need to know how to work out speed?

Cheers

Sheldon
 

CompuChip

Science Advisor
Homework Helper
4,284
47
The easiest way to solve it is using energy balance.
What is the gravitational potential energy and the kinetic energy at the top of the slope?
What is the potential energy and the kinetic energy at the bottom of the slope?
 
11
0
PE1 - mgh
KE1 - MV(Squared)

PE2 - 0
KE2 - Same as PE1

Correct? How does this help tho?
 

CompuChip

Science Advisor
Homework Helper
4,284
47
Almost correct. The formula for KE1 and KE2 is the same, but it is not true that KE1 = KE2.
What velocity do you need to take for V in KE1 and which velocity in KE2?

What can you say about the total energy PE1 + KE1 in relation to PE2 + KE2?
 
11
0
I dont know what velocity I need to take for V in KE1 or KE2 do I?

PE1 + KE 1 = PE2 + KE2 .

There was me hoping there was a simple formular to use, I spent hours looking on net, no wonder I cant find one. Doh
 

CompuChip

Science Advisor
Homework Helper
4,284
47
Well the question is not very clear, but usually the object is at rest at the top of the incline, so there V = 0.
The velocity at the bottom is precisely what you want to calculate. So you can call it V. You will get
PE1 = KE2
Plug in what you know, and solve the equation you wrote down for V.
 
11
0
(Square route)2gh Would give me Velocity but how do I take into account slope?
 

CompuChip

Science Advisor
Homework Helper
4,284
47
It's in h.
The higher the slope, the larger the final velocity.
How long (steep) the slope is doesn't matter, when there is no friction involved.
 
11
0
Ah ok. Thanks

√2x9.81x2.5

=7.00357 m/s
 
11
0
mv²/2 = 2(sx²/2)

X= √mv²/2s

6000x7²/2x30000 - 4.9m

Thanks soooo much!!!
 

CompuChip

Science Advisor
Homework Helper
4,284
47
You're welcome.

Just as an aside, technically the question is talking about "rolling" down the slope, so you should be using rotational formulas (angular momentum, moment of inertia, etc.)
However, as nothing is said about the shape of the wagon, for example, I suppose you'll have to assume that the wagon is sliding down instead of rolling down, which will give you the answer you calculated.
 
11
0
Thanks. Wouldnt I need the friction to work out it angular momentem?

P=ma x f

So Im hoping I have done it correctly
 
It's in h.
The higher the slope, the larger the final velocity.
How long (steep) the slope is doesn't matter, when there is no friction involved.
You mean that the final velocity when the object slides down and free fall is the same?
 

CompuChip

Science Advisor
Homework Helper
4,284
47
Yes, in both cases all potential gravitational energy is converted to kinetic energy.
Only when it slides down an inclined slope, the velocity will decompose into a horizontal and a vertical component.
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top