Calculating Velocity Down a Slope for Railway Wagon Impact

In summary: But the final velocity, as well as the total kinetic energy, will be the same. In summary, the conversation discusses calculating the compression of springs in a railway wagon assessment. The easiest way to solve this problem is by using energy balance and equating the potential and kinetic energies at the top and bottom of the slope. The final velocity of the wagon is calculated using the formula √2gh, where h is the height of the slope. The conversation also touches on the role of friction and the difference between sliding and rolling down a slope.
  • #1
Bikerz
11
0
Hi

Question is-

In the assesment of a buffers performance railway wagon of mass 6 tonne is allowed to roll freely down an incline of 1 in 20 Sine for a distance of 50M into a horizontal yard. At the end of yard is brought to rest by a pair of parrallel springs. The stiffness in each spring is 30kN/m and the intial resistance is 4.5kN. Calculate comprssion of springs.

I can to the final part once I know speed of inpact on springs.

I can't work out speed on wagon as point of impact.
The length of slope is 50m and height will be (50/20 which is 2.5m). I just need to know how to work out speed?

Cheers

Sheldon
 
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  • #2
The easiest way to solve it is using energy balance.
What is the gravitational potential energy and the kinetic energy at the top of the slope?
What is the potential energy and the kinetic energy at the bottom of the slope?
 
  • #3
PE1 - mgh
KE1 - MV(Squared)

PE2 - 0
KE2 - Same as PE1

Correct? How does this help tho?
 
  • #4
Almost correct. The formula for KE1 and KE2 is the same, but it is not true that KE1 = KE2.
What velocity do you need to take for V in KE1 and which velocity in KE2?

What can you say about the total energy PE1 + KE1 in relation to PE2 + KE2?
 
  • #5
I don't know what velocity I need to take for V in KE1 or KE2 do I?

PE1 + KE 1 = PE2 + KE2 .

There was me hoping there was a simple formula to use, I spent hours looking on net, no wonder I can't find one. Doh
 
  • #6
Well the question is not very clear, but usually the object is at rest at the top of the incline, so there V = 0.
The velocity at the bottom is precisely what you want to calculate. So you can call it V. You will get
PE1 = KE2
Plug in what you know, and solve the equation you wrote down for V.
 
  • #7
(Square route)2gh Would give me Velocity but how do I take into account slope?
 
  • #8
It's in h.
The higher the slope, the larger the final velocity.
How long (steep) the slope is doesn't matter, when there is no friction involved.
 
  • #9
Ah ok. Thanks

√2x9.81x2.5

=7.00357 m/s
 
  • #10
mv²/2 = 2(sx²/2)

X= √mv²/2s

6000x7²/2x30000 - 4.9m

Thanks soooo much!
 
  • #11
You're welcome.

Just as an aside, technically the question is talking about "rolling" down the slope, so you should be using rotational formulas (angular momentum, moment of inertia, etc.)
However, as nothing is said about the shape of the wagon, for example, I suppose you'll have to assume that the wagon is sliding down instead of rolling down, which will give you the answer you calculated.
 
  • #12
Thanks. Wouldnt I need the friction to work out it angular momentem?

P=ma x f

So I am hoping I have done it correctly
 
  • #13
CompuChip said:
It's in h.
The higher the slope, the larger the final velocity.
How long (steep) the slope is doesn't matter, when there is no friction involved.

You mean that the final velocity when the object slides down and free fall is the same?
 
  • #14
Yes, in both cases all potential gravitational energy is converted to kinetic energy.
Only when it slides down an inclined slope, the velocity will decompose into a horizontal and a vertical component.
 

1. How is velocity down a slope for railway wagon impact calculated?

The velocity down a slope for railway wagon impact can be calculated using the formula: v = √(2gh), where v is the velocity in meters per second, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the slope in meters.

2. Why is it important to calculate velocity down a slope for railway wagon impact?

Calculating the velocity down a slope for railway wagon impact is important because it allows engineers and scientists to understand the potential speed and force of the wagon as it travels down the slope. This information is crucial for ensuring the safety and stability of the railway system.

3. What factors can affect the velocity down a slope for railway wagon impact?

The velocity down a slope for railway wagon impact can be affected by factors such as the weight and size of the wagon, the angle of the slope, frictional forces, and external forces acting on the wagon such as wind or other objects.

4. How does the velocity down a slope for railway wagon impact affect the design and construction of railway systems?

The velocity down a slope for railway wagon impact is an important factor to consider in the design and construction of railway systems. It can impact the slope angle, track materials, and safety features that need to be implemented to ensure the stability and efficiency of the railway system.

5. Can the velocity down a slope for railway wagon impact be controlled or adjusted?

Yes, the velocity down a slope for railway wagon impact can be controlled or adjusted through various methods such as changing the slope angle, implementing friction brakes, or using other safety mechanisms. However, it is important to carefully calculate and consider all potential impacts and safety measures before making any adjustments to the velocity down a slope for railway wagon impact.

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