What is the velocity due to gravity between two point masses?

That's it.In summary, when two objects of negligable radius and masses M and m are fixed in space at the distance R, and gravity is the only force acting between them, the resulting model using point masses can lead to the incorrect conclusion that the speed of the smaller object when it collides with the larger object is infinite. This is because the model assumes zero initial kinetic energy and a finite potential energy, resulting in an infinite change in kinetic energy at the point of collision. This issue arises from the use of point masses in the model.
  • #1
cromata

Homework Statement


-Two objects of negligable radius and masses M and m are fixed in space at the distance R. Gravity is the only force acting between those two bodies. At some point in time, body of mass m is realized and starts moving due to gravity toward statical mass M.
Find v(x) and speed of body m when it collides with M [x is the distance between the objects]

Homework Equations


F=GMm/r2

The Attempt at a Solution


GMm/(R-x)^2=m dv/dt
GM/(R-x)^2 =dv*v/dx
GM ∫dx/(R-x)^2=∫v*dv [integral of dx goes from 0 to x, and v from 0 to v]
GM*[1/(R-x)-1/R]=½(v^2)
v(x)=sqrt(2GM/R) * sqrt[x/(R-x)]
and for this function, we get that the speed at the moment of impact (x=R) is infinity
-Same result is obtained using energy conservation law, but it doesn't make sense to me
 
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  • #2
cromata said:
GMm/(R-x)^2=m dv/dt
If x is the distance between the two objects as you claim, is this expression consistent with Newton's Law of gravitation?
 
  • #3
I made mistake, I found v(R-x)... but I'm not interrsted in that part of the problem (it's trivial). I just want to know why is v=infinity when two objects collide. Is it because in this sort of the problem we can't say that radius of objects is negligable?
-Because this result doesn't make any sense, for example if we have some object (some asteroid or smth) falling on Earth and we say that Earth's radius is negligable in comparison with the starting distance between Earth and that object, we would obtain that speed of that object is infinite when it hits Earth.
-Also if we have 2 small charges that attract each other (one is fixed, other is free to move) and distance between them is much larger than their radius. We would again obtain same result: infinite speed at the moment of collision.
 
  • #4
The result that v = infinity when the two objects collide is an artifact of the model that assumes that there is such a thing as a point mass or point charge. Reason it out. You start with zero kinetic energy and finite potential energy. As the objects come closer, you convert potential energy to kinetic. Since the initial kinetic energy is zero, the instantaneous kinetic energy at point x is the absolute value of the change in potential energy. What happens to that change at x = 0 where the potential energy is infinite according to the model?
 
  • #5
Gravitational potential energy at the beging of the motion is finite number (Egp1), and when they collide Egp2=-infinity
Ek(kintetic energy at the moment of colision)=|Egp1-Egp2|=infinity, hencr v=infinity. So the problem is in using point masses
 
  • #6
cromata said:
So the problem is in using point masses
Yup.
 

1. What is the velocity due to gravity?

The velocity due to gravity, also known as the escape velocity, is the minimum speed needed for an object to escape the gravitational pull of a celestial body, such as a planet or moon, and enter into a stable orbit.

2. How is the velocity due to gravity calculated?

The velocity due to gravity is calculated using the formula v = √(2GM/r), where G is the gravitational constant, M is the mass of the celestial body, and r is the distance from the center of the celestial body to the object.

3. What is the significance of the velocity due to gravity?

The velocity due to gravity is significant because it determines the speed at which an object needs to travel in order to overcome the gravitational pull of a celestial body, and is essential for space travel and satellite orbits.

4. Does the velocity due to gravity vary on different celestial bodies?

Yes, the velocity due to gravity varies depending on the mass and size of the celestial body. For example, the escape velocity on Earth is 11.2 km/s, while on the moon it is only 2.4 km/s.

5. Can the velocity due to gravity be exceeded?

Yes, it is possible for an object to have a velocity greater than the escape velocity. However, this would require a continuous source of propulsion to counteract the gravitational pull, and is not sustainable for most objects.

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