You're 6.0 m from one wall of a house. You want to toss a ball to your friend who is 6.0 m from the opposite wall. The throw and catch each occur 1.0 m above the ground. V Assume the overhang of the roof is negligible, so that you may assume the edge of the roof is 6.0 m from you and 6.0 m from your friend. What minimum speed will allow the ball to clear the roof? okay i figured out this much so far: delta x= 9m 9= (Vo cos theta)T delta y=5 5= (Vo sin theta)T- .5gt^2 Vy=Vosintheta - gt=0 t=Vosintheta / g and now i know i am suppose to plug in T into the x equation and y equation to solve for Vo, but i cant figure out to do that?