Velocity in polar coordinates

  • Thread starter srmeier
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  • #1
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Homework Statement



I don't understand why when we derive the velocity equation of motion in polar coordinates we start with position equal to R times R hat and not (theta times theta hat + R times R hat).

Homework Equations



none really..

The Attempt at a Solution



Is there an assumption I'm missing? or is it simply differentiating linear and angular velocity that is messing me up?
 
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Answers and Replies

  • #2
vela
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It's because your position is given by

[tex]\vec{R} = \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} R\cos\theta \\ R\sin\theta \end{pmatrix} = R\begin{pmatrix} \cos\theta \\ \sin\theta \end{pmatrix} = R \hat{R}[/tex]

Also, if you think about it, [tex]\theta \hat{\theta}[/tex] doesn't have units of length, so it's not a displacement and you can't add it to [tex]R\hat{R}[/tex].
 

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