1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Velocity in uniform circular motion

  1. Mar 14, 2005 #1
    A 300-m tall tower is built on the equator. How much faster does a point at the top of the tower move than a point at the bottom?
  2. jcsd
  3. Mar 14, 2005 #2


    User Avatar
    Science Advisor

    {Period of Earth's Rotation} = T = (86400 sec)
    {Radius of Earth} = R
    {Tower Bottom Speed} = 2*Pi*R/T
    {Tower Top Speed} = 2*Pi*(R + 300 meters)/T

    {Tower Top Speed} - {Tower Bottom Speed} = {2*Pi*(R + 300 meters)/T} - {2*Pi*R/T} =
    = 2*Pi*(300)/T
    = 2*Pi*(300)/(86400)
    = (0.02182 m/sec)

  4. Mar 14, 2005 #3
    hey bro how did you get the T=86400 sec? thanx for your help, it was the correct answer!
  5. Mar 14, 2005 #4


    User Avatar
    Science Advisor
    Gold Member

    Mugzieee, how long is a day?
  6. Mar 14, 2005 #5
    sorry, that was a thoughtless question which i realized afterwards. thank you :blushing:
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Velocity in uniform circular motion