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Velocity of a block on a slope

  1. Aug 15, 2009 #1
    1. The problem statement, all variables and given/known data

    The block of mass 500 kg is released from rest at the top of the slope
    It slides down a ramp of angle 20degrees
    It raises a block weight of 100kg
    The coefficient of kinetic friction between the 500 kg mass and the ramp is 0.2


    2. Relevant equations

    Determine the velocity of the 100 kg block when it has ascended 5 m

    3. The attempt at a solution

    Hi.

    Im not very good with maths and physics and i'll freely admit that. I just need somehelp in prodding me in the right direction :smile:

    this is what i did so far and it really doesnt look right

    acceleration = 9.81 (sin20 - 0.2cos20)
    (500-100)/1.51

    = 264.63m/s (first thing that makes me think im doing the wrong thing)

    then v squared = 0 + (2*264.63*5)

    = 51m/s


    Now even to someone as thick as me that looks completely wrong. So can someone help me out
     
  2. jcsd
  3. Aug 15, 2009 #2

    kuruman

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    How did you get the expression for the acceleration? It looks like the acceleration of a single mass sliding down the incline. It seems you did not take into account the 100 kg block.
     
  4. Aug 15, 2009 #3
    Here is a pic of the diagram in question


    That acceleration part was something that i found in some notes for a question that i had done ages ago
     

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  5. Aug 15, 2009 #4

    kuruman

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    I cannot see the picture yet. Until I do, ask yourself whether the acceleration that you found in some old notes applies to the same situation as this one. Do you have a description of the old problem with a diagram that matches the picture that you posted?
     
  6. Aug 15, 2009 #5
    no i dont unfortunately

    i dont even have a scanner to scan it into my computer and show you.


    I did find the diagram that goes with the old equation and it doesnt have a weight to raise up. Thats where my equation has gone wrong (amongst other things i guess)
     
  7. Aug 15, 2009 #6

    kuruman

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    That's OK. Eventually the picture will show up. Meanwhile,

    1. Draw a free body diagram (FBD) for each of the masses.
    2. Use the FBDs to write Newton's 2nd Law for each of the masses. This will give you two equations and two unknowns, the common acceleration of the masses and the tension in the string connecting the masses.
    3. Eliminate the tension to find the common acceleration.
     
  8. Aug 15, 2009 #7
    Ok i'll try and draw a free body diagram

    Bare with me cos im not that great at this
     
  9. Aug 15, 2009 #8

    kuruman

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    Take your time, but note that two (not one) FBDs are needed.
     
  10. Aug 15, 2009 #9
    Ok here are my FBD's. I dont know if they are right tho unfortunately
     

    Attached Files:

  11. Aug 15, 2009 #10

    kuruman

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    I cannot see the FBDs "pending approval."
     
  12. Aug 15, 2009 #11
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