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Velocity of a projectile

  1. Apr 12, 2004 #1
    projectile is fired w/an angle of 28.0degrees above the horizontal and from height 46.0m agove the ground. the projectile strikes ground w/a speed of 1.95xVo. Find Vo

    I started using the eqution
    (Vfy)^2=(Voy)^2+2*Ay*(delta Y)

    Voy=Vosin(theta)=.47Vo
    Vfy=1.954*Vosin(theta)=.92Vo

    (.92Vo)^2=(.47Vo)^2+(2*-9.8*-46)
    Vo=37.9

    but my answer is wrong and I can't think of another way to answer the problem.....Any ideas?

    Thanks for your time!
     
  2. jcsd
  3. Apr 12, 2004 #2
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