Calculate the veolcity of a proton of energy 0.12 keV
proton mass = 1.7 x 10^-27
The Attempt at a Solution
0.12 keV = 120 eV
120/1.60 x 10^-19 = 7.5 x 10^20 J
E = 0.5mv^2
sqrt(2E/m) = v
but I'm getting something to x 10^23 so its obviously wrong.
its A-Level physics so shouldnt be a really complex answer...
Going wrong somewhere but cant work it out. Probably where I divided by the charge of an electron?
Any help appreciated.