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jfischer

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- Thread starter jfischer
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- #1

jfischer

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- #2

quark

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- #3

FredGarvin

Science Advisor

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[tex]q = YCA \sqrt{\frac{2g(144) \Delta P}{\rho}}[/tex]

Where:

[tex]q[/tex] = Volumetric flow in [tex]\frac{ft^3}{sec}[/tex]

[tex]Y[/tex] = Expansion Factor

[tex]C[/tex] = Flow coefficient. C can be calculated from the discharge coefficient by:

[tex]C = \frac{C_d}{\sqrt{1-\beta^4}}[/tex]

[tex]\beta[/tex] = Ratio of small to large diameters in the nozzle and pipe

[tex]A[/tex] = Cross sectional area in ft^2

[tex]g[/tex] = Acceleration due to gravity 32.2[tex]\frac{ft}{sec^2}[/tex]

[tex]\Delta P[/tex] = Pressure differential across nozzle in [tex]\frac{Lb_f}{in^2}[/tex]

[tex]\rho[/tex] = Weight density in [tex]\frac{Lb_f}{ft^3}[/tex]

I'll reiterate Quark's suggestion to get Crane's TP. It's worth it's weight in gold.

- #4

jfischer

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thanks for the help. An aproximation will be enough and I will look into the refrence suggested.

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