Velocity of bullet

  • #1

Homework Statement



Agent Arlene devised the following method of measuring the muzzle velocity of a rifle (the figure below). She fires a bullet into a 4.064-kg wooden block resting on a smooth surface, and attached to a spring of spring constant k = 164.5N/m . The bullet, whose mass is 7.870 g, remains embedded in the wooden block. She measures the maximum distance that the block compresses the spring to be 9.460cm .
(Figure 1)

http://session.masteringphysics.com/problemAsset/1696765/3/Giancoli7.ch11.p22.jpg

What is the speed v of the bullet?


2. Homework Equations

v=√(k/m)*x

The Attempt at a Solution



i tried using that equation and different variations but my mastering physics says i'm incorrect.
 

Answers and Replies

  • #3
i tried using √164.5/(4.064+.00787) *.0946


i also tried using .5mv^2=.5kx^2
 
  • #4
662
307
Mech. energy is not conserved in inelastic collisions. Use momentum conservation and then use Energy conservation.
 
  • #5
i cant tell if the question want the velocity before the collision or after the collision.
 
  • #6
3,741
418
It says "muzzle velocity". So it is not the velocity after collision.
 
  • #7
so then should i not use the equation i did ?
 
  • #8
what equation should i use
 
  • #9
301
7
You should use energy conservation.
The kinetic energy of the bullet before collision = the potential energy of spring after collision
 
  • #12
301
7
so 1/2mv2=mgh?
The potential energy of the spring not the gravitational potencial energy(which would stay constant as the system is horizontal)
 
  • #14
301
7
that's right
 
  • #15
would x be the compression of the block after the bullets hit?
 
  • #16
301
7
Yes,right.x would be the compression after bullet hits it.
 
  • #17
mass should be in kg or gr?
 
  • #18
301
7
Wait i think we cant use the conservation of energy here as the mechanical energy is not conserved.Instead we will use conservation of momentum
 
  • #19
so then i would use m1v1right?
 
  • #20
301
7
My answer is coming to be 329m/s.
 
  • #21
301
7
First ignore the spring and calculate the momentum as
mv =(m+M)v1
Now apply the enrgy coonservation
(M+m)v1^2=kx^2
find the value of v1 and then put it in first equation.You will get the answer.
 

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