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MePhysics
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Homework Statement
An electron is projected with an initial speed 1.50×10^6 m/s into the uniform field between the parallel plates in the figure . Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates.
the plates distance apart is .01m
the plates length is .02 m
looks kinda of like this ..
------------------------------ - (+)
-e
--------------------------------- (-)
that's how it looks initially
If the electron just misses the upper plate as it emerges from the field, find the speed of the electron as it emerges from the field?
The Attempt at a Solution
so initial velocitys::
x:: Vo = given
(Vox is the same as Vx )
y:: Vy = 0
accelartion::::
Ax=0
Ay=Fy/m = -eE/m
time:::
delta X = Vox*t + (ax=0 so 0)
t= 1.33*10^-8 seconds
this is where I am stuck...
i need to find Vy and then V=Sqrt(Vx^2 +Vy^2) right?
i have Vx already... how do i get Vy...
i can find it if i know Ay or E but i dont...
any help? please ; thank you
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