1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Velocity of the wedge

  1. Mar 27, 2003 #1
    I think this may be correct I just need a second set of eyes on it to look it over. Thanks in advance.

    The question is:

    A small block of mass m1 =0.500kg is released from rest at the top of a curve shaped frictionless wedge of mass m2=3.00kg, which sits on a frictionless horizontal surface. When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right

    a) what is the velocity of the wedge after the block reaches the horizontal surface

    b) what is the height h of the wedge

    anyway

    a)
    Pwedge=-Pblock
    Mwedge*Vwedge=-Mblock*Vblock

    Vwedge=(-mBlockVblock)/mWedge = -(0.500)*(4)/3
    Vwedge= 0.667 m/s

    b)
    Ki+Ugi=Kf+Ugf

    (0+Mblock*g*h=1/2*Mblock*V^2block + 1/2*Mwedge*v^2wedge+0)

    h= (1/2*Mblock*V^2block + 1/2*Mwedge*v^2wedge)/gMblock

    h=(4+.668)/4.9
    h=0.953 m

    any input?
     
  2. jcsd
  3. Mar 27, 2003 #2
    Looks OK to me. Better use 2/3 than .668
     
  4. Mar 27, 2003 #3
    naa, this is a physics class, not a Calculus class. Exact numbers rounded to 3 places is best.

    Thanks for the check.

    Peace out bro

    M2k
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Velocity of the wedge
  1. Accelerating Wedge (Replies: 2)

  2. Wedge problem (Replies: 38)

  3. Block on the wedge (Replies: 3)

  4. Friction and Wedges (Replies: 9)

Loading...