- #1

mighty2000

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The question is:

A small block of mass m1 =0.500kg is released from rest at the top of a curve shaped frictionless wedge of mass m2=3.00kg, which sits on a frictionless horizontal surface. When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right

a) what is the velocity of the wedge after the block reaches the horizontal surface

b) what is the height h of the wedge

anyway

a)

Pwedge=-Pblock

Mwedge*Vwedge=-Mblock*Vblock

Vwedge=(-mBlockVblock)/mWedge = -(0.500)*(4)/3

Vwedge= 0.667 m/s

b)

Ki+Ugi=Kf+Ugf

(0+Mblock*g*h=1/2*Mblock*V^2block + 1/2*Mwedge*v^2wedge+0)

h= (1/2*Mblock*V^2block + 1/2*Mwedge*v^2wedge)/gMblock

h=(4+.668)/4.9

h=0.953 m

any input?