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Velocity, position and time

  1. Sep 9, 2009 #1
    1. The problem statement, all variables and given/known data
    A particle moving along an x-axis with constant velocity is at the point x=1 when t=2 and is at the point x=5 when t=4. Find the velocity of the particle if x is in meters and t is in seconds. Find an equation that expresses x as a function of t.


    2. Relevant equations



    3. The attempt at a solution
    I got the first part. (4-2)/(5-1) = 0.5m/s. Now, how do I get the equation that expresses x as a function of t?
     
  2. jcsd
  3. Sep 9, 2009 #2

    kuruman

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    You got the first part by assuming that the object covers equal distances in equal times. Can you write an equation that expresses that?

    ** Edit **

    Actually you did not get the first part. You divided time interval by displacement.
     
    Last edited: Sep 9, 2009
  4. Sep 9, 2009 #3
    Oh, so would the velocity be 2?
    Ok, so x=2t+?
    So, it is 2t-3.
    Right?
     
    Last edited: Sep 9, 2009
  5. Sep 9, 2009 #4

    kuruman

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    Yes, x is directly proportional to time, the constant of proportionality being the velocity. To find the velocity, you need to do part (a) correctly. The y intercept in this case is the position of the particle at time t = 0.
     
  6. Sep 9, 2009 #5
    So when time = 0, the particle is at coordinate x=-3.
     
  7. Sep 9, 2009 #6

    kuruman

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    You got it.
     
  8. Sep 9, 2009 #7
    Thanks for notifying me of my mistake!
     
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