1. The problem statement, all variables and given/known data On a dry road, a car with good tires may be able to brake with a constant deceleration of 4.06 m/s2. (a) How long does such a car, initially traveling at 23.6 m/s, take to stop? 5.813 s This answer is correct. (b) How far does it travel in this time? I've tried 59.47 m and 137.1868 but Webassign says both are incorrect. I have no clue as to what I am doing wrong. 2. Relevant equations x(t)= initial position + final velocity * time v(t)= (acceleration * time) + initial velocity x(t)= .5 * (acceleration * (time^2)) + (initial velocity * time) + inital position x= initial position * (average velocity * time) average velocity= (final velocity - initial velocity) / (2) (final velocity^2) - (initial velocity^2) = 2 * acceleration * change in position 3. The attempt at a solution I got 59.47 meters by pluging in part a, 5.813 seconds, into the position function. Then I tried 137.19 meters after figuring that in 5.813 seconds at 23.6 m/s (I multiplied the two) it could travel 137.19. Any ideas on what I am doing wrong?