1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Velocity question

  1. Sep 17, 2006 #1
    Ok:

    Note: Acceleration due to gravity: g = 9.8 m/s

    A feather is dropped inside a vacuum chamber.

    A) What is the Velocity after 0.30 sec?

    B) How far has it fallen after 0.30 sec?

    I'm stuck on this.. it seems simple.. but maybe too simple. I think there is more too it. Any help?
     
  2. jcsd
  3. Sep 17, 2006 #2

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Welcome to the Forums,

    According the the policy one is supposed to show ones efforts before asking for assistance.
     
  4. Sep 17, 2006 #3
    Umm.. I said I was stuck. I do not know where to begin at? Help me?
     
  5. Sep 17, 2006 #4

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Acceleration is the rate of change of velocity with respect to time. Now, if an object is accelerating at 9.8 m/s/s (note the units) how fast will it be going after 1 second? 0.3 seconds?
     
  6. Sep 17, 2006 #5
    after 1 sec it will go 9.8 right? and after .3 sec it will go 2.94.. i think.
     
  7. Sep 17, 2006 #6

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Sounds good to me. Now, for the second question what kinematic equations do you know?
     
  8. Sep 17, 2006 #7
    for distance I have d = 1/2at (the 't' is squared , but I don't know how to type a small '2' next to it.. if you could show me that too please) this is an equation for the problems where acceleration info is already is included.

    where initial velocity is included: d= InitialVelocity x (t) + 1/2a x (t squared)
     
  9. Sep 17, 2006 #8

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Your first equation looks applicable here :smile:. To type superscript text simply enclose the text in [#sup#] [#/sup#] tags (without the #).
     
  10. Sep 17, 2006 #9
    ok I got .441 meters for the distance which I think sounds right. Almost a half a meter. But could you give me an example of how to do the superscript thing again? Is it [/then the number]? or [#the number#] ? Just show me an example of how you would type it.
     
  11. Sep 17, 2006 #10

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    For example if you wanted to type x2, you would type:
    Code (Text):
    x[#sup]2[/sup#]
    Or for subscript;
    Code (Text):
    x[#sub]2[/sub#]
    Again, without the # marks.
     
  12. Sep 17, 2006 #11
    ok thanks soo much for your help.. you don't know how much it is appreciated. I will be back many a times probably until about january.

    let me try - x 2
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Velocity question
  1. Velocity question (Replies: 5)

  2. Velocity question (Replies: 12)

  3. Velocity questions (Replies: 16)

Loading...