A person runs around an equilateral triangle. Each side is 53.3 meters. The person runs completely around the triangle once and 2/3's of the way around the triangle, and the average speed for this trip is 10 m/s. What is the magnitude of the amount of the average velocity for this trip? How do you do this??
velocity = distance over time.
The Attempt at a Solution
the guy ran 53.3 meters x 5 which = a total of 266.5 meters. I divided that by 10 and get 26.65. But thats not the answer. Whats the answer and how do you do it?